The diagram shows a 5cm x 5cm x 5cm cube calculate the length of the diagonal ab
Answers
Solution :-
Refer to Image first .
From image we have :-
→ ABCDEFGH is a cube.
→ CF = Diagonal of cube.
→ CH = Diagonal of Base Face BCDH .
→ Let side of Each cube = a .
Than ,
in Right ∆CFH, By Pythagoras Theoram , we have,
→ CH² + FH² = CF² --------- Equation (1)
and, Similarly, in Right ∆CDH ,
→ CD² + DH² = CH² ------- Equation (2).
Putting Value of Equation (2) in Equation (1) , we get,
→ (CD² + DH²) + FH² = CF²
→ a² + a² + a² = CF²
→ CF² = 3a²
→ CF = √3a .
Hence, we can say That, Diagonal of a cube is √3 times of its sides.
__________________
Given :-
- Side of cube = 5cm.
So,
→ Diagonal of cube = √3 * 5 = 5√3 cm. (Ans.)
___________________
Solution :-
Refer to Image first .
From image we have :-
→ ABCDEFGH is a cube.
→ CF = Diagonal of cube.
→ CH = Diagonal of Base Face BCDH .
→ Let side of Each cube = a .
Than ,
in Right ∆CFH, By Pythagoras Theoram , we have,
→ CH² + FH² = CF² --------- Equation (1)
and, Similarly, in Right ∆CDH ,
→ CD² + DH² = CH² ------- Equation (2).
Putting Value of Equation (2) in Equation (1) , we get,
→ (CD² + DH²) + FH² = CF²
→ a² + a² + a² = CF²
→ CF² = 3a²
→ CF = √3a .
Hence, we can say That, Diagonal of a cube is √3 times of its sides.
__________________
Given :-
Side of cube = 5cm.
So,
→ Diagonal of cube = √3 * 5 = 5√3 cm. (Ans.)
___________________