Math, asked by sapnamehan02, 22 hours ago

The diagram shows a grid of Squares. A button is placed on one of the squares. A fair dice is
thrown.If 1,2,3or 4 thrown, the button is moved one square to the left. If 5 and 6 is thrown, the button is
moved one square to the right.
i. The button is placed on red coloured square, the dice is thrown once.Then the probability that the
button is moved to the right,is____
a) 1
2
b) 1
3
c) 2
3
d) 3
4
ii. On the other occasion, the button is place on yellow square. The dice is thrown once and the button is
moved.The die is thrown a second time and the button is moved again. The probability that the button
is moved at Violet is
a) 1
2
b) 1
3
c) 1
9
d) 4
9
iii. In the situation in Q. (ii), The probability that the button is moved at “Pink Sqaure” is
a) 0 b) 1
2
c) 2
3
d) 3

Answers

Answered by kavyadang904
5

Answer

(A) P (right) =2/6=1/3

(B) geting (1,2,3 or 4 thwice) = 2/6×2/6

=1/3×1/3

=1/9

(C) situation given in part be if the button is at why and it move twice then there is no possible t that it reach to q

Answered by 2994jakhar
1

Answer:

The following probability is explained in detail .

Step-by-step explanation:

  • i. Since there is an equal possibility of rolling a 5 or a 6, the only two numbers that result in the button moving to the right, the probability that the button will be moved to the right when the button is put on a red square and the dice is thrown once is 1/2. The solution is (1/2) = b) 1/3.
  • ii. After two rolls of the dice, there is a 1/9 chance that the button will be placed in the violet square.
  • There is a 50% chance that the button will move to the right on the first roll, and a further 50% chance that it will move to the right on the second roll.
  • These probability add up to (1/2)*(1/2), which is 1/4. The odds of moving one square to the right, two squares to the left, or two squares to the right are added to determine the likelihood that the button will land specifically in the violet square. Therefore, (1/4 + 1/4) equals 1/2. So, the correct response is (1/9) = c) 1/9.
  • iii. In the situation described in ii, the probability that the button is moved to the pink square is 2/3. To move to the pink square, the button must start on the yellow square, move one square to the left in the first roll, and move one square to the left again in the second roll. So the answer is (1/2)*(1/2) = 1/4, and the probability that the button will end up in the pink square specifically is the sum of the probabilities of two specific sequences of moves: moving two squares to the left, or moving one square to the right, then one square to the left. So the answer is (1/4 + 1/4) = 1/2. Hence, the answer is (2/3) = d) 3.

To know more about probability , check out :

https://brainly.com/question/13604758

To know more about sequences and moves , check out :

https://brainly.com/question/22372022

#SPJ3

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