The diagram shows a parallelogram.
The area of the parallelogram is greater
than 10.5 cm
a) Show that 2x2 - 25x + 33 < 0
b) Find the range of possible values of x.
(3)
Note: Write your final answer in the format ... <x<...
Answers
Answer:
3/2 < x < 11
Step-by-step explanation:
Let us name the parallelogram ABCD in cyclic order from the leftmost vertex. So, as provided in the question :
Length AD = (12 - x) cm
Length CD = ( 2x - 1 ) cm
Angle C = 150 degrees
Let us draw a perpendicular from vertex A on the base CD touching it at point E. Thus, the triangle AED formed is right-angled at E.
a) The equation is satisfied by calculating the parallelogram's area.
As the sum of adjacent vertices of a parallelogram sum up to 180 degrees,
∠C + ∠D = 180°
∠D = 180° - ∠C
= 180° - 150°
= 30°
Applying the rules of trigonometry in triangle AED :
The Area of the given parallelogram ABCD
Area = (Base of the parallelogram i.e. CD) * ( height i.e. AE )
Hence, proved that given the area of the parallelogram is greater than 10.5 sq. units, the equation is true.
b) The possoble range for value pf "x" is between (3/2) and 11 i.e.
" (3/2) < x < 11 ".
The equation above is :
Equation 1 : The first term is positive
Equation 2 : The second factor is negative for the product to be negative
Hence, the range of possible values of x is 3/2 < x < 11.
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