Physics, asked by ezhilkumar10, 3 months ago

The diagram shows a ray of light reflected at a
plane mirror.
What is the angle of reflection and angle between
the normal and incident ray ?

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Answers

Answered by MrSanju0123
355

 {\huge{ \large{ \boxed{ \boxed{ \underline{ \sf{ \purple{ \star{Answer{ \star}}}}}}}}}}

\boxed{ \green{\bf{Angle\:of\:Reflection = 30^{\circ}}}}

Angle between the normal and the incident ray = 30°

Explanation:

Let AO be the incident ray, Let OB be the reflected ray and Let M, M ' be the plane mirror..

Let us name the parts of the mirror

  • AO = Incident Ray

  • OB = Reflected Ray

  • M, M' = Mirror

To Find

  • Angle of Reflection

  • Angle between the normal and incident ray

SolutioN

Firstly Let us find the angle between the normal and incident ray. We know that normal is perpendicular to the mirror. So, Normal = 90°.

Given that the glance angle of incidence[I.e the Angle between the incident ray and the normal] = 60°[ I.e Angle Between The Mirror And The Incident ray]

So, Angle of Incidence = 90° - 60°

Angle of Incidence = 30° .

So, according to the Laws of Reflection

  • Angle of Incidence = Angle of Reflection

  • Angle of Incidence = 30°

  • So, \boxed{ \green{\bf{Angle\:of\:Reflection = 30^{\circ}}}}

So, angle between the incident ray and the Normal [I.e The Angle of Incidence] = 30°


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