Question

The diagram shows a right-angled triangle and parallelogram.
The area of the parallelogram is four-time the area of the triangle.
Find the value of h

Answer 1

Question:

The area of the parallelogram is four-time the area of the triangle.

Find the value of h.

Given:

The Area of the Parallelogram is 4 times the Area of the Triangle . It is also given that Height of the Triangle is 7cm and Base of the Triangle is 4cm. while the base of parallelogram is 14cm

To Find:

The Height of the Parallelogram

Formulas Used:

$\textsf{Area of triangle} = \frac{1}{2}\times base \times height$

$\textsf{Area of Parallelogram }=base \times height$

$\textsf{Height of the Parallelogram} =h=\frac{A}{b}$

Solution:

Area of the triangle :

Area of the triangle = $\frac{1}{2}\times base \times height$

$\frac{1}{2}\times4\times 7\\\\\\=\frac{1}{1}\times2\times7\\\\\\=1\times2\times7\\\\\\=14cm^2$

Therefore Area of the Triangle is 14cm²

Area of the Parallelogram :

Area of the Parallelogram = $b\times h$

But the area of the Parallelogram is 4 times area of triangle

$=4\times14\\\\=56cm^2$

Area of the Parallelogram = 56cm²

Height of the Parallelogram :

Height of the Parallelogram = $h=\frac{A}{b}$

$\to h=\frac{56}{14}\\\\\\\to h=\frac{28}{7}\\\\\\=\frac{4}{1}\\\\\\\boxed{=4cm}$

Height of the Parallelogram = 4cm

Answer:

Height of the Parallelogram = 4cm

Be Brainly!

Answer 2

Refer to above answer