The diagram shows a square of side length 10 cm. A quarter circle, of radius 10 cm is drawn from each vertex of a square. find the exact area of the shaded region.
This is from As level Book by Sue Pemberton. page 110 Q12
Answers
Answer:
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Answer:
100 ( π/3 + 1 - √3) cm²
31.5 cm²
Step-by-step explanation:
we need to find Area of A
As this is a square and radius are all equal
Hence region mentioned have equal areas
B = C = D = E
F = G = H = I
Point F if joined with both bottom vertex of square then its = 10
as its on arc of radius = 10
and hence form an equilateral triangle
so Area of A + D + E + H = (60/360) π 10² + (60/360) π 10² - (√3 / 4)10²
= 100 ( π/3 - √3 / 4)
Area of A + D + E + H + C + G = (90/360) π 10² = 100 π/4
Area of C + G = 100 π/4 - 100 ( π/3 - √3 / 4)
= 100 ( √3 / 4 - π/12)
C+ G = D+H = E + I = B + F
=> B + C + D + E + F + G + H = 4 * 100 ( √3 / 4 - π/12) = 100 (√3 - π/3)
Area of A = Area of Square - Area of ( B + C + D + E + F + G + H)
= 10² - 100 (√3 - π/3)
= 100 ( π/3 + 1 - √3)
= 31.5 cm²