Question

The diagram shows observer 'O' and object
'A'. What will be the distance between '0
and image of 'A' in mirror?
​

Answer 1

Answer:

10 root 2

Explanation:

distance between a and image of a = 10cm

distance between o and image of a = root (10^2 + 10^2) using pythagorous

hence distance = 10 root 2

Answer 2

Given: The diagram shows observer 'O' and object 'A'.

To find: The distance between '0 and image of 'A' in mirror.

Solution: The distance between '0 and image of 'A' in mirror is 11.18 cm.

In the given diagram the perpendicular distance between O (observer) and A (object) is given. Also, the perpendicular distance between A and the mirror where the image is formed is given. If we draw a line joining O to the mirror (M), then it would form a right-angled triangle.

Here, OA would form the perpendicular, AM would form the base and OM would form the hypotenuse. Thus, we can use the Pythagoras theorem to calculate the hypotenuse which is the distance between O and the image of A in the mirror.

$OM = \sqrt{10^{2} + 5^{2} }$

       $= 11.18$

Therefore, the distance between '0 and image of 'A' in mirror is 11.18 cm.