Question

The diagram shows parts of two regular polygons A and B. A has 10 sides and exterior angle ax. B has exterior
angle 2x Work out the number of sides regular polygon B has???
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Answer 1

Answer:

each exterior angle = 360/ no of side

exterior angle 3x = 360/10

3x = 36

x=12

now put the value of x in B

2x= 24

exterior agle of b is 24 so

no of side = 360/ one angle

No of side = 360/ 24

= 15