Question

The diagram shows the inner boundary of a 600m
Running track witch has two parallel straight lines each of length 200m and two semicircular ends.
Assuming π =3.142,calculate the radius of each semi -circular end correct to the nearest 1÷100m. Solve this question

Answer 1

Given :-

• Inner boundary of a track = 600m .
• AB = ED = 200m.

To Find :-

• Radius of each semi -circular end .

Solution :-

→ AB + ED + circumference of two circular end with diameter as AE and BD = 600 m..

→ 200 + 200 + circumference of one circle = 600 m

→ circumference of one circle = 600 - 400

→ circumference of one circle = 200m.

Now, Let the radius of both semi-circle is equal to r.

So,

→ circumference of circle = 2πr

→ 2 * 3.142 * r = 200m

dividing both sides by 2,

→ 3.142 * r = 100m.

dividing both sides by 3.142,

→ r = 31.82m .(Ans.)

Hence, radius of each semi -circular end is 31.82m .