Question

The diagram shows the path of a track. ABC and DEF are two semicircular arcs, each of radius 7 m and AF = CD= 20 m.
$(\pi = \frac{22}{7} )$
(i) Find the length of the semicircular are ABC.
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Answer 1

Answer:

Radius of the curves =100m

Weight =100kg

Velocity =18km/hr=5m/sec

(a) AT B=mg−

R

mv

2

=N⇒N=(100×10)−

100

100×25

=1000−25=975N

At D,N=mg+

R

mv

2

=1000+25=1025N

(b) At B and D the cycle has no tendency to slide. So at B and D, frictional force is zero.

At C, mgsinθ=F⇒F=1000×

2

1

=707N

(c) (i) before C mgcosθ−N=

R

mv

2

⇒N=mgcosθ−

R

mv

2

=707−25=683N

(ii) N−mgcosθ=

R

mv

2

⇒N=

R

mv

2

+mgcosθ=25+707=732N

(d) To find out the minimum desired coeff. of friction, we have to consider a point just before C (where N is minimum)

Now, μN=mgsinθ⇒μ×682=707⇒μ=1.037

Answer 2

Answer:

Hey friend

Your answer is 22 m.

I hope it's help you please.

Sorry for late answering. There is something problem in mobile phone and don't mind if I am not answering your any question I tried to give your answer.