The dial of a galvanometer has 21 cuts (zero to 20) i.e. 20 divisions. It has a frequency of 1 division over 10 la current. Its impedance is 20 2, so how do you turn it into an emitter that can measure (a) 1 A current? (b) Now convert the original galvanometer to 1 v. How to convert a voltmeter that measures the difference in potential? And find the effective resistance of both the above meters.
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