The diameter and length of a roller are 70 cm and 100 cm respectively it moves once over to level a playground of area 4400 m square find the number of revolution the roller will take to level the playground.
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First of all find the C.S.A of roller(cylinder) then divide it by the area of square playground....
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D=70cm R=35cm H=100cm
CSA=2πrh=11000cm^2 in one round
4400m^2=4400×100×100cm^2
no of rounds =44000000/11000=4000rounds
CSA=2πrh=11000cm^2 in one round
4400m^2=4400×100×100cm^2
no of rounds =44000000/11000=4000rounds
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