The diameter and length of a roller are 70cm and100cm respectively.It moves once over to level a playground of area 4400m².find the no of revolution the roller will take to level the playground.
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Answer:
2000 Revolutions.
Step-by-step explanation:
Given that the diameter of the roller,d=70 cm and height=100 cm.
Then, Radius of the roller,r = d/2 = 70/2 cm =35 cm
The length covered per revolution = the curved surface area of the roller = 2πrh = 2×22/7×35 cm × 100 cm = 22000cm²=22000cm²÷10000cm²=2.2m²[ 1 m² = 10000 cm² ]
Total Area To Cover = 4400 m²
∴Required No. of Revolutions = 4400m²/2.2m² = 2000
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