Question

The diameter and length of a roller is 120 cm
and 84 cm respectively. To level the ground,
200 rotations of the roller are required. Find
the expenditure to level the ground at the rate
of 10 per sq. m.​

Answer 1

Answer:

Radius of roller

Area of Roller = curved surface area of cylinder

= 2πrh cm^2

here π = 22/7

r = radius

h = height

In 200 rotations of roller area covered =

because in one rotation roller covers 31680 cm^2

In 200 rotations of roller area covered =

per sq m expenditure is 10 Rs

so for 633.6 m^2, total expenditure is

Explanation:

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