Math, asked by Anonymous, 5 months ago

the diameter of a 120 cm long roller is 84 cm It takes 1000 complete revolutions in moving once over to level a playground what is the area of the playground​

Answers

Answered by Anonymous
2

★Solution :

___________________________

➪ Length of roller = 120 cm.

➪ Diameter of roller = 84 cm.

➪ Radius of roller = \dfrac{(Diameter)}{2}

= \dfrac{84}{2}

= 42 cm

___________________________

As we know, a roller is in the shape of cylinder.

➪Perimeter of roller = Area covered by roller in 1 one revolution = 2 × π × (radius ) × length

➪Perimeter = 2×( \dfrac{22}{7} ) × 42 × 120

➪Perimeter = 44 × 6 × 120

➪Perimeter = 31,680 cm²

____________________________

Therefore,

➪Area covered by wheel in 1000 revolutions

= (31,680×1000) cm²

= \dfrac{31,680,000}{10000}

Answer = 3,168m²

Hence, Area of Playground is 3,168m²

______________________________

Answered by devroy26780
4

Step-by-step explanation:

Radius of the roller (r)=

2

84

cm=42cm

length of the roller (h)=120cm

∴ Area of the playground levelled in taking 1 complete revolution 2πrh

=2×227×42×120=31680cm

2

∴ Area of the playground

=31680×500=15840000cm

2

100×100

15840000

m

2

=1584m

2

Similar questions