Math, asked by tanzeelasiddiqui97, 16 days ago

the diameter of a 120cm long roller is 84cm. it takes 1000 complete revolution moving once over​

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Answered by vishvsolanki25
0

Step-by-step explanation:

Radius of the roller (r) = 84/ 2 cm = 42 cm

Length of the roller (h) = 120 cm

Curved surface area of the roller = 2πrh

= 2 × 22/ 7 × 42 × 120 cm2 = 44 × 720 cm2= 31680 cm2

∴ area covered by the roller in 1 revolution = 31680 cm2

∴ area covered by the roller in 1000 revolutions = 31680 × 1000 cm2 = 31680000 cm

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500 revolution kaise liya aapne

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raj123458

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here you can radius = 84/ 2 cm = 42 cm & roller=120 or, area of the roller = 2πrh

= 2 × 22/ 7 × 42 × 120 cm2 = 44 × 720 cm2= 31680 cm2

∴ area covered by the roller in 1 revolution = 31680 cm2

∴ area covered by the roller in 500 revolutions = 31680 × 500 cm2 = 15840000 cm

therefore area = 15840000/ 100× 100 m2 = 1584 m2 Ans.

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but 100* 100 kyu kiya 1000 revolution ke liye

raj123458 avatar

so that is area of revolution =500 & area of playground=500×31680cm2 & u will be calculator

one more question solve it plz

find the CSA of a garden roller whose length and diameter are 1.5m and 1.4m how much area can it level in 200 revolution

raj123458 avatar

area of playground =15840000cm2 but u need ans in meter so you know that 1m = 100cm so, 1cm2= 1/100 ×1/100. & then you dived from area of the playground u will be answerthank you

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