Math, asked by pathancool19, 3 months ago

the diameter of a 2.5 m long roller is 92 cm . if its take 150 revolution to level a playground then find the approximate cost of levelling the ground at the rate of 60 paise per square meter ( π - 22 / 7 ​

Answers

Answered by josephinediamalekudy
1

Step-by-step explanation:

Diameter= 2.5m

length= 92cm,

1m=100cm

2.5m=250cm

let length be height

Radius=diameter÷2

Radius=250/÷2

Radius=125cm

area of curved surface =2πrh

2× 22÷7 ×125× 92=

506000/7=72285.714cm^2

it took 150 revolutions, So

72285.714× 150= 10842857.1cm

Cost of levelling the ground= 60 paise

10842857.1× 60= 650571426 paise

1 paise = 1÷100 ruppees

650571426÷100= 6505714.26 ruppees

So, our answer is = 6505714.26 ruppees

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