The diameter of a circle is 50 cm. A chord is
at a distance of 7 cm from the centre of the
circle. Find the length of the chord.
Answers
given:
d=2r
r=25cm
let O be centre
and AB is chord
M is perpendicular to chord from centre of circle
OM=7cm
answer:
by using Pytagores theorem,
OA^2=OM^2+AM^2
25^2-7^2=AM^2
(25+7) (25-7) =AM^2
32×18=AM^2
AM^2=576
AM^2=√576
AM^=24
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ANSWER
Diameter = 50.
radius = diameter / 2 = 50/2 = 25.
Whenever perpendicular is drawn from center of circle to a chord, it bisects.
Distance from center to chord = 7 cm.
It is a 7 cm length perpendicular from center to chord, it will bisect the chord.
It makes a right angle triangle.
By Pythagoras theorem,
length of half chord = √(25)^2 — (7)^2 = 24.
Length of chord = 2 x 24 = 48 cm
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