Question

the diameter of a circle is 50cm.A chord at a distance of 7cm from the centre of the cirle.find the lenght of the cord.
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Answer 1

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Diameter = 50.

radius = diameter / 2 = 50/2 = 25.

Whenever perpendicular is drawn from center of circle to a chord, it bisects.

Distance from center to chord = 7 cm.

It is a 7 cm length perpendicular from center to chord, it will bisect the chord.

It makes a right angle triangle.

By Pythagoras theorem,

length of half chord = √(25)^2 — (7)^2 = 24.

Length of chord = 2 x 24 = 48 cm

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Answer 2

Answer:

given:

d=2r

r=25cm

let O be centre

and AB is chord

M is perpendicular to chord from centre of circle

OM=7cm

answer:

by using Pytagores theorem,

OA^2=OM^2+AM^2

25^2-7^2=AM^2

(25+7) (25-7) =AM^2

32×18=AM^2

AM^2=576

AM^2=√576

AM^=24

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