Question

The diameter of a circle measures 24mm. What is the circumference of the circle?


Use 3.14 for Pi , and do not round your answer. Be sure to include the correct unit in your answer.

Can you please help me with this question?

Answer 1

Answer:

Name Perimeter Total Surface Area Curved Surface Area/Lateral Surface Area Volume Figure

Square 4a a2 —- —- Square

Rectangle 2(w+h) w.h —- —- Rectangle

Parallelogram 2(a+b) b.h —- —- Parallelogram

Trapezoid a+b+c+d 1/2(a+b).h —- —- Trapezoid

Circle 2 π r π r2 —- —- Circle

Ellipse 2π√(a2 + b2)/2 π a.b —- —- Ellipse

Triangle a+b+c 1/2 * b * h —- —- Triangle

Cuboid 4(l+b+h) 2(lb+bh+hl) 2h(l+b) l * b * h Cuboid

Cube 6a 6a2 4a2 a3 Cube

Cylinder —- 2 π r(r+h) 2πrh π r2 h Cylinder

Cone —- π r(r+l) π r l 1/3π r2 h Cone

Sphere —- 4 π r2 4π r2 4/3π r3 Sphere

Hemisphere —- 3 π r2 2 π r2 2/3π

Step-by-step explanation:

Name Perimeter Total Surface Area Curved Surface Area/Lateral Surface Area Volume Figure

Square 4a a2 —- —- Square

Rectangle 2(w+h) w.h —- —- Rectangle

Parallelogram 2(a+b) b.h —- —- Parallelogram

Trapezoid a+b+c+d 1/2(a+b).h —- —- Trapezoid

Circle 2 π r π r2 —- —- Circle

Ellipse 2π√(a2 + b2)/2 π a.b —- —- Ellipse

Triangle a+b+c 1/2 * b * h —- —- Triangle

Cuboid 4(l+b+h) 2(lb+bh+hl) 2h(l+b) l * b * h Cuboid

Cube 6a 6a2 4a2 a3 Cube

Cylinder —- 2 π r(r+h) 2πrh π r2 h Cylinder

Cone —- π r(r+l) π r l 1/3π r2 h Cone

Sphere —- 4 π r2 4π r2 4/3π r3 Sphere

Hemisphere —- 3 π r2 2 π r2 2/3π

Answer 2

Answer:

Given :-

• The diameter of a circle measures 24 mm.

To Find :-

• What is the circumference of the circle.

Solution :-

☆ First, we have to find the radius of the circle :

Given :

• Diameter = 24 mm

According to the question by using the formula we get,

$\implies \sf\boxed{\bold{Radius =\: \dfrac{Diameter}{2}}}$

So, by putting the value we get,

$\implies \sf Radius =\: \dfrac{24}{2}$

$\implies \sf Radius =\: \dfrac{12}{1}$

$\implies \sf\bold{\underline{Radius =\: 12\: mm}}$

Hence, the radius of the circle is 12 mm .

☆ Now, we have to find the circumference of the circle :

Given :

• Radius = 12 mm
• Pie (π) = 3.14

According to the question by using the formula we get,

$\implies \sf\boxed{\bold{Circumference_{(Circle)} =\: 2{\pi}r}}$

where,

• π Pie or 22/7 or 3.14
• r = Radius

So, by putting those values we get,

$\implies \bf Circumference_{(Circle)} =\: 2{\pi}r$

$\implies \sf Circumference_{(Circle)} =\: 2 \times 3.14 \times 12$

$\implies \sf Circumference_{(Circle)} =\: 6.28 \times 12$

$\implies \sf\bold{\underline{Circumference_{(Circle)} =\: 75.36\: mm}}$

$\therefore$ The circumference of the circle is 75.36 mm .