The diameter of a circle whose area is equal to the sum of the areas of the two circles of radii 40cm and 9cm is
Answers
Answered by
37
Answer:
Diameter of the given circle is
82cm.
Step-by-step explanation:
Given,
Radius of first circle = 40cm
Radius of second circle = 9cm
Area of the circle = sum of areas of two circles
πR² = π x 40² + π(9)²
=> R² = 1600 + 81
=> R² = 1681
=> R = √1681
=> R = 41cm
Therefore,
Diameter of the given circle = 41 x 2 = 82cm.
Answered by
1
Answer:
let the radius of circle be r
then,A.T.G.C.
pi x r2= pi(40 ^2 + 9 ^2)
r2=400+81
r2=4081
r=41
d=82
Step-by-step explanation:
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