Question

the diameter of a circular coil is 31.4*10^-2m and its number of trun 400.for what amount of current flow in the coil the magnetic field at the centre of the coil will be 4*10^-4wb^-2​

Answer 1

Answer:

Magnetic field at center due to one ring is B.

Hence, due to n ring is B,

B=nB

1

where n=500turns.

B

1

=

2r

μ

0

I

where I=current through ring, r=radius of ring.

B=500×

2×π×10

−2

4π×10

−7

×5

=5×10

−2

=0.05T