The diameter of a circular garden is 140 m. On its outside, there is a road 7 m wide. Find the area of the road and the cost of levelling the road at 5 per sq metre.
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Step-by-step explanation:
Answer:
Radius of circle = 140/2=70M
Area of circle = πr^2 = 22/7×70×70
============= =====15400sq M
Radius including road = 70+7=77
Area = πr^2 = 22/7×77×77
====================== 18634 sq. m
Area of Road (levelling)=18634-15400
===================== 3234 sq. m
Cost of levelling road = 3234×1.5
= 4851 rupees
Answer ----4851
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Answer:
980 is the correct✔ answer please mark brillant answer
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