Math, asked by bhanupartapshukla817, 5 months ago

The diameter of a circular park is 140 m. Around it on the outside, a path having the
width of 7 m is constructed. If the path has to be fenced from inside and outside at the
rate of rupees7 per metre, find its total cost.
217​

Answers

Answered by ishitakumar3267
2

Step-by-step explanation:

We have to find the inside distance and outside distance.

for inside distance , radius = 140/2 =70 m

length of circumference =2π×radius

=2×(22/7)×70

=440 m

now, outside distance

radius = 70 +7 = 77 m

length of circumference = 2π× radius

= 2×(22/7)×77

= 484 m

total length = 440 +484 =924 m

cost = Rs 7× 924 = Rs 6468

Answered by Anonymous
9

Answer:

 \underline{ \sf{ \underline{Given:}}}

  • Diameter of circular park = 140m
  • width = 7m

 \underline{ \sf{ \underline{Find:}}}

  • Total cost

 \underline{ \sf{ \underline{Solution:}}}

For inside distance:-

Diameter = 140m

We know that ⬇️

{ \boxed{ \sf{Diameter = 2 \times Radius}}}

So, Radius = 70m

From ⬇️

{ \boxed{ \sf{Circumference = 2πr}}}

{ \implies{2 \times  \frac{22}{7}  \times 70 = 440m}}

Therefore Circumference of inside = 440m

For outside distance:-

Radius = 70+7 = 77

Circumference = 2πr

{ \implies{2 \times  \frac{22}{7}  \times 77 = 484m}}

Therefore Circumference of outside = 484m

Total length = 440+484 = 924

Cost = 7 × 924 = 6468

{ \therefore{ \sf{Total \: cost \:  = Rs.6468}}}

I think my answer will help you

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