Question

The diameter of a circular park is 24m. A 3m wide path runs around it from inside. Find the cost of paving the path at ₹ 25sq m

Answer 1

Answer:

diameter of outer circle=24m

therefore,area of total circular park=

$\pi {r}^{2}$

=(22/7)×(24/2)×(24/2)

=452.5sq m

diameter of inner circle=24-3

=21m

therefore,area of inner circle=

$\pi {r}^{2}$

=(22/7)×(21/2)×(21/2)

=346.5sq m

therefore,area of path=452.5-346.5

= 106sq m

therefore coat of paving the path=106×25

=₹2650

Answer 2

Answer:

₹4950

Step-by-step explanation:

Let the diameter of the

circular park ( D ) = 24 m

Radius of the park ( R ) = D/2

R = 24 /2 = 12 m

If the width of the path inside the

park ( w ) = 3m

Radius of the inside circle (r ) = R - w

r = 12 - 3 = 9 m

Area of the path ( A ) = πR² - πr²

A = π(R + r ) (R - r )

= π ( R + r ) w

= ( 22 /7 ) ( 12 + 9 ) ( 3 )

= 22 × 3 × 3

A = 198m²

Cost of the paving the per square

meter = Rs 25

Cost of paving total area of the path

=25 × 198

= Rs4950

I hope this helps you.

:)