Question

The diameter of a circular park is 28 m. A road 1.75 m wilde runs around it. Find the cost of gravelling the road at the rate of Rs. 5 per m2​

Answer 1

Answer:

Step-by-step explanation:

Solution now radius =28/2.

.Width of road is 1.75m.

now radius of outer circle is =14+1.75=15.75.

.

.

Area of road=( Area of outer circle - Area of inner circle).

=π×(15 .75)*2-π×(14)*2.

=π×{(15.75)*2-(14)*2}.

=π×{(15.75-14)(15.75+14)}.

π×29.75×1.75.

22/7×29.75×1.75.

=7.4375×22.

.-- >163.625m/sq.

so the cost of road =163.625×5.

.Answer=RS=818.125