The diameter of a circular park is 56 m. A 2 m wide rode runs outside around it. Find the cost of cementing the road at ₹10 per sq m. (Take π=3.14)
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Answer:
d=56m
r=28cm
R=28+ 2
=30m
area of road=[R^2 - r^2]
=22/7 *(30^2 - 28^2)
=22/7*(30+28)(30-28)
=22/7*58*2
= 364.57sq. m
total cost =364.57*10
=rs.3645.7
Step-by-step explanation:
Hope it helps(๑ゝω·)ﾉ♡
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