Math, asked by bhaskarbaura, 4 months ago

The diameter of a circular park is 70 m if the cost of cementing this park is 1000₹ per 100 m ² than find the total cost of cementing this park take π=3.14​

Answers

Answered by AkelaRavan000
3

Step-by-step explanation:

Answer is at attachment....

Attachments:

bhaskarbaura: you use 3.14 formula
AkelaRavan000: yah
bhaskarbaura: give me the answer
bhaskarbaura: what is the answer
AkelaRavan000: is this is answer..
bhaskarbaura: The diameter of a circular park is 70 m if the cost of cementing this park is 1000₹ per 100 m ² than find the total cost of cementing this park take π=3.14
1 point
38465₹
38565₹
38665₹
38765₹
The total cost
bhaskarbaura: which you give the answer is wrong
bhaskarbaura: give me the my question answer fast
AkelaRavan000: sorry i Don't know‍♀️‍♂️
bhaskarbaura: pls do it
Answered by fruity777
4

Answer :-

Total cost of cementing the park = 38465 Rs

Given :-

Diameter of park = 70 m

Rate of cementing = 1000 Rs / 100 m²

Value of pi (π) = 3.14

To Find :-

Total cost of cementing the park = ?

Explanation :-

As above given, we have to find the total cost of cementing the park and thus, first we need to find it's area.

Finding radius of park,

\blue { \boxed { \bf \bigstar \: Radius \: of \: Park = \dfrac{Diameter}{2} \: \bigstar }}

★RadiusofPark=

2

Diameter

\sf : \; \leadsto \dfrac{70}{2} \: m:⇝

2

70

m

\sf : \; \leadsto 35 \: m \qquad \star:⇝35m⋆

Finding area of park,

\pink { \boxed { \bf \bigstar \: Area \: of \: Park = \pi r^2 \: \bigstar }}

★AreaofPark=πr

2

\sf : \; \leadsto 3.14 \times (35)^2 \: m^2:⇝3.14×(35)

2

m

2

\sf : \; \leadsto 3.14 \times 35 \times 35 \: m^2:⇝3.14×35×35m

2

\sf : \; \leadsto 3.14 \times 1225 \: m^2:⇝3.14×1225m

2

\green { \bf : \; \leadsto 3846.5 \: m^2 \qquad \star }:⇝3846.5m

2

Finding the cost of cementing,

: \: \leadsto \text{ \sf Cost of cementing 100 $ \sf m^2 $} = \bold{1000 \: R_S}:⇝ Cost of cementing 100 m

2

=1000R

S

: \: \leadsto \text{ \sf Cost of cementing 1 $ \sf m^2 $} = \dfrac{1000}{100} \: R_S = \bold{ 10 \: R_S}:⇝ Cost of cementing 1 m

2

=

100

1000

R

S

=10R

S

: \: \leadsto \text{ \sf Cost of cementing 3846.5 $ \sf m^2 $},:⇝ Cost of cementing 3846.5 m

2

,

\sf = (3846.5 \times 10) \; R_S=(3846.5×10)R

S

\red { \underline { \boxed { \bf = 38465 \; R_S }}}

=38465R

S

Hence, the total cost of cementing the park is 38465 Rs.

Similar questions