Math, asked by Debarka2008, 4 months ago

The diameter of a circular park is 75m. A 3.5 m wide road runs on the inside around it. Find the cost of constructing the road at ₹200 per square metre.

I need justified answer or else i will report

Answers

Answered by memanan03
12

Area of Road = Area of Circle1 Area of Circle2

= πR² - πr²

(R = 75/2 = 37.5m,

r = 37.5 3.5 = 34m)

= 22/7 (37.5 × 37.5 34 × 34)

= 22/7 × 250.25

= 5505.5/ 7

Area of Road = 786.5

Cost of Construction @200 per

= 786.5 × 200

= Rs. 157300

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Answered by abhijtghoshal2016
3

Area of Road = Area of Circle 1 – Area of Circle2

= πR² - πr²

(R = 75/2 = 37.5m,

r = 37.5 – 3.5 = 34m)

= 22/7 (37.5 × 37.5 – 34 × 34)

= 22/7 × 250.25

= 5505.5/ 7

Area of Road = 786.5 m²

Cost of Construction @200 per m²

= 786.5 × 200

= Rs. 157300

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