Math, asked by tanisha29k2910, 1 year ago

the diameter of a circular Park is 84 metre. on its outside there is 3.5 wide Road. find the cost of constructing the road at rupees 240 per metre square

Answers

Answered by aryanmalik21
2
22/7*44.5*44.5-22/7*41*41=22/7(44.5*44.5-41*41)*240=cost 225720
hope it help...............
Answered by rithurithika632
8

Answer:

=> Cost of constructing = 962.5 × 240

                                       = ₹ 2,31,000

Step-by-step explanation:

Larger circle = Circle B

Smaller circle = Circle A

--------------------------------------------------------------------------------------------------------------=> Radius of Circle A = Diameter ÷ 2 = 84 ÷ 2 = 42 m

=> Area of Circle A = π × r^2

=> Area of Circle A = 22/7 × 42^2

=> Area of Circle A = 22/7 × 1764

=> Area of Circle A = 22 × 252

=> Area of Circle A = 5544 m^2

--------------------------------------------------------------------------------------------------------------=> Radius of Circle B = 42 + 3.5 = 45.5 m

=> Area of Circle B = π × r^2

=> Area of Circle B = 22/7 × (45.5)^2

=> Area of Circle B = 22/7 × 2070.25

=> Area of Circle B = 22 × 295.75

=> Area of Circle B = 6506.5 m^2

--------------------------------------------------------------------------------------------------------------

=> Area of road = Area of Circle B - Area of Circle A

=> Area of road = 6506.5 - 5544

=> Area of road = 962.5 m^2

--------------------------------------------------------------------------------------------------------------

=> Cost of constructing = Area × Cost/m

=> Cost of constructing = 962.5 × 240

=> Cost of constructing = ₹ 2,31,000

HERE IS UR ANSWER I THINK THIS MAY HELP U........

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