The diameter of a circular park is 84m. On its outside there a 3.5m wide road. Find the cost of constructing the road at 240m square
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Answered by
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radius of the park = 84/2 = 42m
area of the park = (22/7)×42×42 = 5544m^2
width of road = 3.5m
.•.total radius = 3.5+42 = 45.5m
total area = (22/7)×45.5×45.5 = 6506.5m^2
area cover by the road=6506.5-5544= 1062.5m^2
total cost of constructing the road=1062.5×240=Rs255000
area of the park = (22/7)×42×42 = 5544m^2
width of road = 3.5m
.•.total radius = 3.5+42 = 45.5m
total area = (22/7)×45.5×45.5 = 6506.5m^2
area cover by the road=6506.5-5544= 1062.5m^2
total cost of constructing the road=1062.5×240=Rs255000
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it is wrong in last step
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34
Answer:
Step-by-step explanation:
radius of the park = 84/2 = 42m
area of the park = (22/7)×42×42 = 5544m^2
width of road = 3.5m
.•.total radius = 3.5+42 = 45.5m
total area = (22/7)×45.5×45.5 = 6506.5m^2
area cover by the road=6506.5-5544= 1062.5m^2
total cost of constructing the road=1062.5×240=Rs255000
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