The diameter of a circular park is 84m. On its outside there a 3.5m wide road. Find the cost of constructing the road at 240m square
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2r=84m (given)
r =84/2=42m
outer circle's radius=42+3.5=45.5m
inner circle's radius=42m
area of path = (area of outer circle) - (area of inner circle)
cost of constructing the road is =240×area of path.
r =84/2=42m
outer circle's radius=42+3.5=45.5m
inner circle's radius=42m
area of path = (area of outer circle) - (area of inner circle)
cost of constructing the road is =240×area of path.
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