Question

The diameter of a circular park is 84m. On its outside there a 3.5m wide road. Find the cost of constructing the road at 200m square​

Answer 1

Answer:

Radius of park = 84/2 = 42m

Area of road = π(45.5² - 42²)

= 962.5 m²

Cost = Area*Rate

= 962.5*200

= ₹ 192500

Answer 2

$\underline{\boxed{\bold{ \bigstar \; Question \; \bigstar }}}$ $\; \; \; \;$

The diameter of a circular park is 84m. On its outside there a 3.5m wide road. Find the cost of constructing the road at 240m square.

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Diameter of the park = 84 m

Radius of the park = $\frac{84}{2}$ = 42 m

Area of the park = πr²

                           = $(\frac{22}{7})$ (42)²

                           = 5544 m²

Width of the road = 3.5 m

Total radius = 3.5 + 42

                    = 45.5

Total area = πr²

                 = $(\frac{22}{7})$ (45)²

                 = 6506.5 m²

Area covered by the road = Total area - Area of the park

                                            = 6506.5 m² - 5544 m²

                                             = 1062.5 m²

Total cost of constructing the road = Rate × Area

                                                          = 1062.5 × 200

                                                          = 212500

∴ Cost of constructing the road at 200m² = Rs. 212500

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