Math, asked by rakhi1dey, 2 months ago

The diameter of a circular park is 98 m. On its outside, there is a 3.5 m wide road. Find the cost of

constructing the road at Rs.327 per square metre


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Answers

Answered by bradlamar691
1

Answer:

Rs.365095.5

Step-by-step explanation:

The Diameter of the Circular Park(d) = 98 meters

⇒The Radius of the Circular Park(r) = \frac{d}{2} = 49 meters

Width of Road(w) = 3.5m

⇒The Radius of the Circular Park including the Road(R) = r + w = 52.5 meters

∴The Area of the Road = Area of Park including Road - Area of Circular Park

Area of Park including Road = \pi R^{2} ; Area of Park = \pi r^{2}

⇒Area of The Road(A) = \pi R^{2} -\pi r^{2}

A = \pi (R^{2} -r^{2})

A = \pi (2756.25 - 2401)

A = \pi (355.25)

A = \frac{22}{7} *355.25

A = 22*50.75

A = 1116.5 m^{2}

Cost of constructing the Road = Rs.327 per m^{2}

⇒Cost of constructing a 1116.5 m^{2} Road = 327*1116.5 = Rs.365095.5

Answered by maqsadahsan
1

Answer:

1825

1825- 1826

William Sturgeon (British) invents the electromagnet, a coil of wires with an iron core to enhance the magnetic field.

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