the diameter of a circumference park is 94.4 a 2.8 m wide road is constructed outside the circular park i around it find the cost of paving this road at the rate of rupees 50 per secure metre
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Answer:
$4950
Step-by-step explanation:
Since the Diameter=24m. The Radius will be =D/2=24/2=12m.
It is given that a 3m wide path runs around it from 'inside'. Therefore, the Radius of the bigger circle will be 12−3=9m
Area of bigger circle=πr
2
=22/7
∗
12
∗
12=452.57m
2
Area of smaller circle =πr
2
=22/7
∗
9
∗
9=254.57m
2
So the area of path =Area of bigger circle−Area of smaller circle
=452.57−254.57
=198m
2
The total cost=198
ast
25=Rs. 4950.
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