Question

the diameter of a closed cylinder is 21 cm and height is 10 CM find the total surface area of th​

Answer 1

Step-by-step explanation:

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Answer 2

AnswEr :

$\:\:\:\bullet$ Diameter = 21cm

$\:\:\:\bullet$ Height = 10cm

$\:\:\:\bullet$ So; Radius is $\bf\frac{21}{2}$

$\rule{100}2$

$\underline{\bigstar\:\textsf{According \: to \: question:}}$

$\:\:\:\bullet$Formula,that we are going to use;

$\star{\boxed{\sf{T.S.A_{cylinder} = 2 \pi r(r + h ) }}}$

$\:\:\:\bullet$Here;

$\:\:\star$ $\bf\ \pi \: = \; \frac{22}{7}$

$\:\:\star$ $\bf\ r \: = \: radius$

$\:\star$ $\bf\ h \: = \: height$

$\underline{\bigstar\:\textsf{Block \: the \: values \: in \: available \: data:}}$

$\normalsize\hookrightarrow\sf\ T.S.A \: = \: 2 \times\ \frac{22}{7} \times\ \frac{21}{2}[\frac{21}{2} + 10]$

$\normalsize\hookrightarrow\sf\ T.S.A = \cancel{2} \times\ \frac{22}{\cancel{7} } \times\ \frac{\cancel{21} }{\cancel{2} }[\frac{21 + 20}{2}]\\ \\ \normalsize\hookrightarrow\sf\ T.S.A = \cancel{22} \times\ 3 \times\ \frac{41}{\cancel{2} } \\ \\ \normalsize\hookrightarrow\sf\ T.S.A = 11 \times\ 3 \times\ 41 \\ \\ \normalsize\hookrightarrow\sf\ T.S.A = 1331$

$\hookrightarrow{\underline{\boxed{\sf\green{T.S.A_{cylinder} \: = \: 1331 \: cm^2}}}}$