Math, asked by bhaveshdolia, 6 months ago

The diameter of a cone is 28 cm and slant height is 10.5 cm. Then, its lateral surface area is :

(A) 480 cm2 (B) 490 cm2 (C) 462 cm2 (D) 466 cm2​

Answers

Answered by Anonymous
6

Given :-

  • Slant Height = 10.5 cm
  • Diameter = 28 cm
  • Radius = Diameter ÷ 2 = 28 ÷ 2 = 14 cm

To Find :-

  • CSA of cone = ?

Answer :-

  • CSA of cone = 462 cm²

Explaination :-

→ CSA of cone = πrl

→ CSA of cone = 22/7 × 14 × 10.5

→ CSA of cone = 22 × 2 × 10.5

→ CSA of cone = 44 × 10.5

CSA of cone = 462 cm²

Therefore,Lateral Surface Area of cone is (C) 462 cm².

_____________________

Extra Shots :-

  • Volume of cylinder = πr²h
  • T.S.A of cylinder = 2πrh + 2πr²
  • Volume of cone = ⅓ πr²h
  • C.S.A of cone = πrl
  • T.S.A of cone = πrl + πr²
  • Volume of cuboid = l × b × h
  • C.S.A of cuboid = 2(l + b)h
  • T.S.A of cuboid = 2(lb + bh + lh)
  • C.S.A of cube = 4a²
  • T.S.A of cube = 6a²
  • Volume of cube = a³
  • Volume of sphere = 4/3πr³
  • Surface area of sphere = 4πr²
  • Volume of hemisphere = ⅔ πr³
  • C.S.A of hemisphere = 2πr²
  • T.S.A of hemisphere = 3πr²
Answered by Aɾꜱɦ
6

\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}} \\

\leadsto\bf \dfrac{Diameter}{2} = Radius\\\\

\leadsto\bf  \cancel\dfrac{28}{2} = Radius\\\\

\leadsto\underline{\boxed{\textsf{ {\textbf{462 cm²}}}}} \qquad\qquad \bigg\lgroup\bold{Radius } \bigg\rgroup\\\\

\small\underline\textsf{ Formula Used:- }

{\underline{\overline{\mid{\mathsf{\purple{\:\: Curved \:surface\: area\: of\: circle = \pi rl\:\:} \mid}}}}}\\\\

\small\underline\textsf{ Putting the values:-}

\leadsto\bf Curved\: surface \:area \:of \:circle = \dfrac{22}{7} \times \cancel{14} \times 10.5 \\ \\

\leadsto \bf Curved\: surface \:area\: of \:circle = 44 \times 10.5 \\\\

\leadsto\bf Curved \:surface \:area \:of \:circle = 462 cm^2  \\\\

\small\underline\textsf{ Hence:-}

\underline{\boxed{\textsf{Lateral surface area = {\textbf{462 cm²}}}}} \qquad\qquad \bigg\lgroup\bold{Option \ C \ is \ Correct } \bigg\rgroup

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