the diameter of a cylinderical roller is 9.1cm,and it's 2.8m long. find the area it will cover in 30 revolution.
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Step-by-step explanation:
The radius of a cylindrical roller is 4.55 cm. The height of the cylinder is 2.8 meter long. So, Area of 1 revolution is 80.08 cm². Area of 30 revolution is 2402.4 cm².
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Answer:
Step-by-step explanation:
R=9.1/2=4.55m
The surface area of roller=
2\pi \: r( \: h + r)
2×22/7×4.55(2.8+4.55)
210.21m^2
Area it will cover in 30 revolution=210.21×30
=6306.3m^2
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