The diameter of a cylindrical roller is 9.1 cm, and it is 2.8 m long. Find the area it will cover in 30 revolutions.
Answers
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Step-by-step explanation:
Area of 30 revolution is 2402.4 cm².
Step-by-step explanation:
Given : The diameter of a cylindrical roller is 9.1 cm, and is 2.8 m long.
To Find : The area it will cover in 30 revolutions ?
Solution :
The diameter of a cylindrical roller is 9.1 cm.
The radius of a cylindrical roller is 4.55 cm.
The height of the cylinder is 2.8 meter long.
The area of the roller = Curved surface of cylinder
A=2\pi r hA=2πrh
A=2\times \frac{22}{7}\times 4.55\times 2.8A=2×
7
22
×4.55×2.8
A=80.08\ cm^2A=80.08 cm
2
So, Area of 1 revolution is 80.08 cm².
Area of 30 revolution is 80.08\times 3080.08×30
Area of 30 revolution is 2402.4 cm².
#Learn more
A cylindrical road roller is 1 m long. Its inner diameter is 54 cm and thickness of the iron sheet rolled into the road roller is 9 cm. Find the weight of the roller, if 1 cm^3 iron weighs 8 gm (pi = 3.14).