Math, asked by jajejgata7014, 1 year ago

The diameter of a flowerbed in a garden is 2.8m Find the cost of fencing it at a rate of RS 55per m.


anup3147: hhh
Dadaruhikeshe: RS 484

Answers

Answered by TPS
110

\text{ Diameter = 2.8 m}\\ \\ \text{Perimeter =} \:  \pi D = \frac{22}{7} \times 2.8 = 8.8\ m\\ \\ \text{Rate of fencing = Rs. 55 per m}\\ \\ \text{Total cost = } 55 \times 8.8=\ Rs.\ 484

Answered by Anonymous
98

According to the Question

Diameter of garden = 2.8

Radius of the garden  

\bf\huge R = \frac{2.8}{2}

R = 1.4 m

Perimeter of the garden = 2πr

\bf\huge = 2\times \frac{22}{7} \times 1.4

= 8.8 Metre

Therefore

Cost of fencing = Perimeter × Rate  

= 8.8 × 55

= ₹ 484


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Dadaruhikeshe: RS 484
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