The diameter of a garden cylindrical roller is 2.8 m long . How much area will it cover in 100 revolutions
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Answered by
1
Answer: 616 sq. m
Step-by-step explanation:
d = 2.8m, r= d/2, A=pi r^2
r = 2.8/2 = 1.4m
Area, 1 revolution = 22/7 x 1.4 x 1.4
A = 6.16 sq. m
1 rev. = 6.16 sq. m
100 rev. = (6.16 x 100)/1
= 616 sq. m
Answered by
0
Answer:
insufficient data, height of cylinder to be mentioned. 880h
Step-by-step explanation:
880h, where height is h
please find attachment
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