Math, asked by amykhuranna, 10 months ago

The diameter of a garden cylindrical roller is 2.8 m long . How much area will it cover in 100 revolutions

Answers

Answered by yeipyeng04
1

Answer: 616 sq. m

Step-by-step explanation:

d = 2.8m, r= d/2, A=pi r^2

r = 2.8/2 = 1.4m

Area, 1 revolution = 22/7 x 1.4 x 1.4

A = 6.16 sq. m

1 rev. = 6.16 sq. m

100 rev. = (6.16 x 100)/1

= 616 sq. m

Answered by onlydanda
0

Answer:

insufficient data, height of cylinder to be mentioned. 880h

Step-by-step explanation:

880h, where height is h

please find attachment

Attachments:
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