Question

The diameter of a garden roller is 1.4 m and it is 2 m long. How much area will it level in 5 revolutions?

Answer 1

in 1 revolution area = (2πr) × (2)
in 5 revolution = 5×2×1.4×π
= 14π

Answer 2

HEY DEAR ... ✌


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Diameter = 1.4 m
r = d/2
r = 1.4/2
r = 0.7m
curved  surface area of cyclinder = 2 * 22/7 * r^2                                                                                                    = 2 * 22/7 * 0.7 * 0.7                                                 = 8.8 m^2
     No of revolution = 5
Therefore  = 8.8 * 5               
   = 44 m2

HOPE , IT HELPS .