Math, asked by barnovokundu, 1 month ago

The diameter of a garden roller is 1.4 m and it is 2 m long. If it needs 100 revolutions to level the garden once . Then What will be the area of the garden ?​

Answers

Answered by guptavishrut
2

Answer:

880 m²

Step-by-step explanation:

The roller is in the form of a cylinder

the diameter of roller=1.4m

radius=diameter/2

=1.4/2

=0.7

height=2m

C.S.A of roller=C.S.A of the cylinder

=2πrh

=2×22/7×0.7×2

=2×22×0.1×2

=44×0.1×2

=8.8 m²

area leveled after 100 revolutions=8.8×100

=880 m²

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