Question

The diameter of a garden roller is 1.4 m and its length is 2m. Find the number of revolutions
required to level a playground that has length 40m and width 11m.​

Answer 1

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Diameter of garden roller=1.4m

Radius =0.7m

Height/length=2m

$\red{\tt{Area \: covered \: in \: 1 \: revolution =}}$

$\red{\tt{CSA \: of \: Cylenderical \: roller}}$

CSA of roller=πrh

${\tt{\pi rh}}$

${\tt{ \frac{22 \times 7 \times 2}{7 \times 10}}}$

${\tt{ \frac{22}{5} = 4.4 {m}^{2}}}$$<font color="red">$

1revolution=4.4m²$<font color="blue">$

Area of playground=40m×11m

Area of playground=440m²

4.4m² can be covered in=1 revolution

440m² can be covered in

=440/4.4

$\purple{\tt{=100 revolutions}}$

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