Math, asked by rishabh6613, 11 months ago

the diameter of a garden roller is 1.4 metre and it is 2 metre long how much will be cover in 20 revolutions​

Answers

Answered by reshmaperween3478
3

Answer:

Area of roller - 2pi r h

2* 22/7 * 1.4/2*2

17.6 m²

Area of 20 revolution - 17.6 m² * 20

352 m²

Answered by lAnniel
3

\huge{\underline{\sf{Question :-}}}}

The diameter of a garden roller is 1.4m and it is 2m long. How much area will it cover in 20 revolutions.

\huge{\underline{\sf{Answer :-}}}}

\sf Given\begin{cases} &\sf{Diameter\;of\;the\; garden\:roller,\:D\;=\be{1.4\:m}}\\&\sf{Width\;of\;the\;garden\: roller,\:h=\;\bf{2\:m}}\end{cases}\\ \\

\boxed{ \sf \red{  To \: Find : }}

✏ Area it will cover in 5 revolutions = ❓

\green{\underline\bold{We \:know\:,}}

✏ Radius, r = \frac{Diameter}{2}

✏ r = \frac{1.4}{2}

✏ r = 0.7 m

\green{\underline\bold{From\:the\:formula,}}

\boxed{ \sf \blue{Area \: of\:the\:roller=\: Curved\:surface\:area\:of\:the\:cylinder }}

= 2Πrh

= 2 × \frac{22}{7} × 0.7 × 2

= 8.8 m sq.

\green{\underline\bold{Now,}}

\boxed{ \sf \blue{ Area\: of \:the\: roller\: it\:will\:cover\: in\: 1 \:revolution=\:area\:of\:the\:roller }}

= 8.8 m sq.

\boxed{ \sf \blue{ Area\: of \:the\: roller\: it\:will\:cover\: in\:20 \:revolutions= }}

= 8.8 × 20

= 176 m sq.

\pink{\underline\bold{∴The\:required\:answer\:is\: = \: 176\: m\: sq.}}

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