Question

The diameter of a garden roller is 1.8m and it is 2.8 m long . How much area will it cover in 25 revolutions in levelling a field​

Answer 1

Answer:

Since the garden roller is cylindrical

The area covered by it in one revolution equals it's curved surface area

Given diameter = 1.8m height = 2.8m

Therefore radius of the roller = 0.9m

Thus we have

Curved surface area = 2πrh

= 2×22/7×0.9×2.8 m².

= 15.84 m².

Thus area covered in 25 revolutions

= 25×15.84 m²

= 396 m²

Hope you understood the solution