the diameter of a internal and external surfaces of a hollow hemispherical shell are 8 cm and 12 CM respectively and recast into a solid cylinder of radius 7 cm then find the height of the cylinder
Answers
Answered by
0
It's done. The answer must be approx 16 or 17 cm
Attachments:
Answered by
0
external diameter =12cm=6cm=radius (R1)
internal diameter =8cm=4cm=radius (R2)
volume of hemisphere =2/3pi(R1^3-R2^3)
=2/3x22/7(216-64)
44/21x152
=6688/21
=318.47cm
radius of cylinder =7cm and let height of cylinder
volume of cylinder =volume of hemisphere
pir^2h=318.47cm
h=318.47/pi r^2
h=318.47/22/7(49)
h =318.47 x(22x7)
h=318.47 /709.2
h=0.4490cm
hence the height of cylinder =0.4490cm
internal diameter =8cm=4cm=radius (R2)
volume of hemisphere =2/3pi(R1^3-R2^3)
=2/3x22/7(216-64)
44/21x152
=6688/21
=318.47cm
radius of cylinder =7cm and let height of cylinder
volume of cylinder =volume of hemisphere
pir^2h=318.47cm
h=318.47/pi r^2
h=318.47/22/7(49)
h =318.47 x(22x7)
h=318.47 /709.2
h=0.4490cm
hence the height of cylinder =0.4490cm
Similar questions