Math, asked by robinbhattarai9671, 11 months ago

The diameter of a lead ball is 2.1 cm. The density of the lead used is 11.34 g/c³. What is the weight of the ball?

Answers

Answered by Govindthapak
12

Step-by-step explanation:

The weight of the ball will be calculated by using the formula which is

mass= density× volume

now we calculate volume of the lead ball

 =  \frac{4}{3} \pi {r}^{3} \\  =  \frac{4}{3}  \times  \frac{22}{7}  \times 2.1 \times 2.1 \times 2.1 \\  = 88 \times 4.41 \times \frac{2.1}{21}  \\  = 88 \times 4.41 \times .1 \\  = 38.8 \: cc

now the mass = 38.8 ×11.34

=439.9 g

= .43kg

this is mass now the weight will be equal to

= mg

where m is mass and g is gravitational acceleration

= .43×10

= 4.3 kg

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