Math, asked by ramanachereku, 18 days ago

The diameter of a lead ball is 2.1 cm. The density of the lead used is 11.34g/c³. what is the weight of the ball.

Answers

Answered by Anonymous
0

Answer:

539

Step-by-step explanation:

weight = mass x g

mass = density x volume

volume = \frac{4}{3} \pir^{3}

r = 2.1/2 cm

∴ Volume = 4.85

and mass = 54.9 ≈ 55

Weight = 55 x 9.8 = 539

Answered by FallenLove
10

Diameter of lead ball=2.1cm

 \sf \pink{Radius(r)= \frac{2.1}{2} cm}

 \sf \blue{Volume=  \frac{4}{3} \: \pi r{}^{3} }

 \sf \implies \orange{ \frac{4}{3}  \times  \frac{22}{7}  \times  \frac{21}{20}  \times  \frac{21}{20}  \times  \frac{21}{20} }

 \sf\implies \orange{4.851cm {}^{3}}

 \sf\fbox \red{Density=11.34g/cm {}^{3} }

 \sf \green{Density=  \frac{Mass}{volume}}

 \sf \pink{11.34 =  \frac{mass}{4.851} }

 \sf \implies \purple{Mass=11.34×4.851g}

 \sf \implies \purple{Mass=55.01g.}

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