The diameter of a lead ball is 2.1 cm.The density of the lead used is 11.34g/c 3.what is the weight of the ball
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radius = 1.05 cm
r^3 = 1.157625
4/3 pi = 4.18879
Volume of sphere = 4/3 pi r^3 = 1.157625*4.18879 = 4.8490 cm^3
density = mass/volume = 11.34 g/cm^3
11.34 g/cm^3 = mass of sphere/volume of ball = mass of ball/4.8490 cm^3
11.34*4.8490 g = 54.988 g = mass of ball
mass*acceleration due to gravity = weight
Converting to SI units
mass of ball = 0.054988 kg
acceleration due to gravity = 9.81 m/s^2
weight of ball = 0.054988*9.81 = 0.539 kgm/s^2 = 0.539 N = answer
Please note the mass must be in kg when multiplying by 9.81 m/s^2 to arrive at newtons!!!!!!!!!!!!!!!!
r^3 = 1.157625
4/3 pi = 4.18879
Volume of sphere = 4/3 pi r^3 = 1.157625*4.18879 = 4.8490 cm^3
density = mass/volume = 11.34 g/cm^3
11.34 g/cm^3 = mass of sphere/volume of ball = mass of ball/4.8490 cm^3
11.34*4.8490 g = 54.988 g = mass of ball
mass*acceleration due to gravity = weight
Converting to SI units
mass of ball = 0.054988 kg
acceleration due to gravity = 9.81 m/s^2
weight of ball = 0.054988*9.81 = 0.539 kgm/s^2 = 0.539 N = answer
Please note the mass must be in kg when multiplying by 9.81 m/s^2 to arrive at newtons!!!!!!!!!!!!!!!!
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